因为满足j−i=k−jj - i = k - jj−i=k−j, 故 我们可以先枚举 jjj, 然后再枚举iii和kkk 到 jjj 的距离 ddd
所以 i=j−di = j - di=j−d 和 k=j+dk = j + dk=j+d, 故时间复杂度O(n2)O(n^2)O(n2)
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markchen
LV 1
SU
@ 2025-2-21 9:03:40